本文介紹了*& 的含義和**&在 C++ 中的處理方法,對大家解決問題具有一定的參考價(jià)值,需要的朋友們下面隨著小編來一起學(xué)習(xí)吧!
問題描述
限時(shí)送ChatGPT賬號(hào)..
我在函數(shù)聲明中多次發(fā)現(xiàn)這些符號(hào),但我不知道它們是什么意思.
I found these symbols in a function declaration several times, but I don't know what they mean.
示例:
void raccogli_dati(double **& V, double **p, int N) {
int ultimo = 3;
V = new double * [N/2];
for(int i=0; i < N/2; i++) {
V[i] = new double[N/2], std :: clog << "digita " << N/2 - i
<< " valori per la parte superiore della matrice V: ";
for(int j=i; j < N/2; j++)
std :: cin >> V[i][j], p[ultimo++][0] = (V[i][j] /= sqrt(p[i][0]*p[j][0]));
}
for(int i=1; i < N/2; i++)
for(int j=0; j < i; j++)
V[i][j] = V[j][i];
}
推薦答案
即以引用方式取參數(shù).因此,在第一種情況下,您通過引用獲取指針參數(shù),因此您對指針值所做的任何修改都會(huì)反映在函數(shù)之外.第二個(gè)與第一個(gè)相似,唯一的區(qū)別是它是一個(gè)雙指針.看這個(gè)例子:
That is taking the parameter by reference. So in the first case you are taking a pointer parameter by reference so whatever modification you do to the value of the pointer is reflected outside the function. Second is the simlilar to first one with the only difference being that it is a double pointer. See this example:
void pass_by_value(int* p)
{
//Allocate memory for int and store the address in p
p = new int;
}
void pass_by_reference(int*& p)
{
p = new int;
}
int main()
{
int* p1 = NULL;
int* p2 = NULL;
pass_by_value(p1); //p1 will still be NULL after this call
pass_by_reference(p2); //p2 's value is changed to point to the newly allocate memory
return 0;
}
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