問(wèn)題描述

我有以下需要在服務(wù)器中轉(zhuǎn)換為 JSON 的 XML 文件.最初我以為我會(huì)將它轉(zhuǎn)換為字典，然后使用 JavaScriptSerializer 將其轉(zhuǎn)換為 JSON，但由于每列可能有不同的值類(lèi)型，我認(rèn)為它不會(huì)起作用.以前有人在 C#/LINQ 中做過(guò)類(lèi)似的事情嗎?

I have the following XML file that I need to convert to JSON in the server. Initially I thought I would convert it to a Dictionary and then use the JavaScriptSerializer to turn it into JSON but since each column could have a different value type, I don't think it would work. Has anyone done something similar before in C#/LINQ?

我需要保留每列的值類(lèi)型(布爾、字符串、整數(shù)).

I need to preserve the Value Types(Boolean, String, Integer) of each column.

如果我剛剛開(kāi)始使用 XML，我將不勝感激.謝謝.

I would appreciate any advice on this as Im just starting to work with XML. Thanks.

<Columns>
 <Column Name="key1" DataType="Boolean">True</Column>
 <Column Name="key2" DataType="String">Hello World</Column>
 <Column Name="key3" DataType="Integer">999</Column>
</Columns>

推薦答案

using System;
using System.Linq;
using System.Web.Script.Serialization;
using System.Xml.Linq;

class Program
{
    static void Main()
    {
        var xml = 
        @"<Columns>
          <Column Name=""key1"" DataType=""Boolean"">True</Column>
          <Column Name=""key2"" DataType=""String"">Hello World</Column>
          <Column Name=""key3"" DataType=""Integer"">999</Column>
        </Columns>";
        var dic = XDocument
            .Parse(xml)
            .Descendants("Column")
            .ToDictionary(
                c => c.Attribute("Name").Value, 
                c => c.Value
            );
        var json = new JavaScriptSerializer().Serialize(dic);
        Console.WriteLine(json);
    }
}

產(chǎn)生:

{"key1":"True","key2":"Hello World","key3":"999"}

顯然，這會(huì)將所有值都視為字符串.如果您想保留底層類(lèi)型語(yǔ)義，您可以執(zhí)行以下操作:

Obviously this treats all the values as strings. If you want to keep the underlying type semantics you could do the following:

using System;
using System.Linq;
using System.Web.Script.Serialization;
using System.Xml.Linq;

class Program
{
    static void Main()
    {
        var xml = 
        @"<Columns>
          <Column Name=""key1"" DataType=""System.Boolean"">True</Column>
          <Column Name=""key2"" DataType=""System.String"">Hello World</Column>
          <Column Name=""key3"" DataType=""System.Int32"">999</Column>
        </Columns>";
        var dic = XDocument
            .Parse(xml)
            .Descendants("Column")
            .ToDictionary(
                c => c.Attribute("Name").Value, 
                c => Convert.ChangeType(
                    c.Value,
                    typeof(string).Assembly.GetType(c.Attribute("DataType").Value, true)
                )
            );
        var json = new JavaScriptSerializer().Serialize(dic);
        Console.WriteLine(json);
    }
}

產(chǎn)生:

{"key1":true,"key2":"Hello World","key3":999}

如果您無(wú)法修改底層 XML 結(jié)構(gòu)，您將需要一個(gè)自定義函數(shù)，該函數(shù)將在您的自定義類(lèi)型和底層 .NET 類(lèi)型之間進(jìn)行轉(zhuǎn)換:

And if you cannot modify the underlying XML structure you will need a custom function that will convert between your custom types and the underlying .NET type:

using System;
using System.Linq;
using System.Web.Script.Serialization;
using System.Xml.Linq;

class Program
{
    static void Main()
    {
        var xml = 
        @"<Columns>
          <Column Name=""key1"" DataType=""Boolean"">True</Column>
          <Column Name=""key2"" DataType=""String"">Hello World</Column>
          <Column Name=""key3"" DataType=""Integer"">999</Column>
        </Columns>";
        var dic = XDocument
            .Parse(xml)
            .Descendants("Column")
            .ToDictionary(
                c => c.Attribute("Name").Value, 
                c => Convert.ChangeType(
                    c.Value, 
                    GetType(c.Attribute("DataType").Value)
                )
            );
        var json = new JavaScriptSerializer().Serialize(dic);
        Console.WriteLine(json);
    }

    private static Type GetType(string type)
    {
        switch (type)
        {
            case "Integer":
                return typeof(int);
            case "String":
                return typeof(string);
            case "Boolean":
                return typeof(bool);
            // TODO: add any other types that you want to support
            default:
                throw new NotSupportedException(
                    string.Format("The type {0} is not supported", type)
                );
        }
    }
}

這篇關(guān)于如何使用 C#/LINQ 將 XML 轉(zhuǎn)換為 JSON?的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，也希望大家多多支持html5模板網(wǎng)！