問題描述
Stackoverflow 上的某個地方有一個問題,雖然我現在找不到了,但它提醒發布者 .value
不會返回 .exist
s 的值.
There is a question somewhere on Stackoverflow, although i cannot find it now, that reminded the poster that .value
does not return the value that .exist
s.
那是因為 .value
總是寫成要求 [1]
項,其中 .exist
到處可見.
That is because .value
is always written as asking for the [1]
item, where .exist
looks everywhere.
假設一個包含兩個客戶的 xml 文檔:
Given a hypothetical xml document containing two customers:
<Customer>
<Name>Ian Boyd</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
</Customer>
<Customer>
<Name>Kirsten</Name>
<IDInfo>
<IDType>3</IDType>
<IDOtherDescription>Firearms Certificate</IDOtherDescription>
</IDInfo>
</Customer>
我想為具有 IDType 的任何客戶返回 Name
、IDType
和 IDOtherDescription
3
(其他):
i want to return the Name
, IDType
, and IDOtherDescription
for any customers who have an IDType of 3
(Other):
DECLARE @xml XML;
SET @xml =
'<Customer>
<Name>Ian Boyd</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
</Customer>
<Customer>
<Name>Kirsten</Name>
<IDInfo>
<IDType>3</IDType>
<IDOtherDescription>Firearms Certificate</IDOtherDescription>
</IDInfo>
</Customer>'
--Wrap it up in a table, cause it makes it look more like my real situation
;WITH BatchReports AS (
SELECT @xml AS BatchFileXml
)
SELECT
BatchFileXml.value('(//Name)[1]', 'varchar(50)') AS Name,
BatchFileXml.value('(//IDType)[1]', 'varchar(50)') AS IDType,
BatchFileXml.value('(//IDOtherDescription)[1]', 'varchar(50)') AS IDOtherDescription,
*
FROM BatchReports
--WHERE BatchFileXml.value('(//IDType)[1]', 'varchar(50)') = '3'
WHERE BatchFileXml.exist('//IDType[text()="3"]')=1
由于 .exist
is 滿足,所以返回一行:
Since the .exist
is satisfied, it returns a row:
Name IDType IDOtherDescription
-------- ------ --------------------
Ian Boyd 1 Firearms Certificate
除非那不是我想要的.我想要 IDType = 3
的值.
Except that's not what i wanted. I wanted the values where IDType = 3
.
事情變得更加復雜,其中有多個 IDType
條目:
Things get even more complicated, where there are multiple IDType
entries:
<Customer>
<Name>Ian Boyd</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
</Customer>
<Customer>
<Name>Kirsten</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
<IDInfo>
<IDType>2</IDType>
</IDInfo>
<IDInfo>
<IDType>4</IDType>
</IDInfo>
<IDInfo>
<IDType>3</IDType>
<IDOtherDescription>Firearms Certificate</IDOtherDescription>
</IDInfo>
</Customer>
當您可以在其他級別找到 /IDInfo
節點時,情況會更加復雜:
And even more complicated when you can find /IDInfo
nodes in other levels:
<Customer>
<Name>Ian Boyd</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
<ThirdPartyInfo>
<IDInfo>
<IDType>3</IDType>
<IDOtherDescription>Sherrif Badge</IDOtherDescription>
</IDInfo>
</ThirdPartyInfo>
</Customer>
<Customer>
<Name>Kirsten</Name>
<IDInfo>
<IDType>1</IDType>
</IDInfo>
<IDInfo>
<IDType>2</IDType>
</IDInfo>
<IDInfo>
<IDType>4</IDType>
</IDInfo>
<IDInfo>
<IDType>3</IDType>
<IDOtherDescription>Firearms Certificate</IDOtherDescription>
</IDInfo>
</Customer>
最終結果是一樣的.我需要一個查詢來返回 exist
的 values
:
The end result is the same. I need a query to return the values
that exist
:
Name IDType IDOtherDescription
-------- ------ --------------------
Ian Boyd 3 Sherrif Badge
Kirsten 3 Firearms Certificate
獎金聊天
當我兩年前設計系統并選擇使用 XML
數據類型時,我認為在緊急情況下它會很有用.我可以使用一些 XPath 來過濾原始 xml.我忘記了 XPath 和 SQL Server 中的 XPath 是多么不可能.四個小時盯著文檔和網站;我又餓又累.
Bonus Chatter
When i designed the system two years ago, and chose to use XML
data type, i figured it would be useful when there's an emergency. I can use some XPath to filter through the raw xml. I forgot how impossible XPath, and XPath in SQL Server is. Four hours of staring at documentation and web-sites; i'm hungry and tired.
推薦答案
以下是您可以嘗試的查詢:
Here is the query you can try:
;WITH BatchReports AS (
SELECT @xml AS BatchFileXml
)
SELECT a.BatchXml.value('(Name)[1]', 'varchar(50)') AS Name,
a.BatchXml.value('(IDInfo/IDType)[1]', 'varchar(50)') AS IDType,
a.BatchXml.value('(IDInfo/IDOtherDescription)[1]', 'varchar(50)') AS IDOtherDescription
FROM BatchReports b
CROSS APPLY b.BatchFileXml.nodes('Customer') A(BatchXml)
WHERE a.BatchXml.exist('IDInfo/IDType[text()=3]')=1
這里是從所有 XML 中檢索必要信息的查詢.
and here is the query which retrieve necessary information form all of the XMLs.
;WITH BatchReports AS (
SELECT @xml AS BatchFileXml
)
SELECT A.BatchXml.value('(Name)[1]', 'varchar(50)') AS Name,
B.BatchXml.value('(IDType)[1]', 'varchar(50)') AS IDType,
B.BatchXml.value('(IDOtherDescription)[1]', 'varchar(50)') AS IDOtherDescription
FROM BatchReports X
CROSS APPLY X.BatchFileXml.nodes('Customer') A(BatchXml)
CROSS APPLY A.BatchXml.nodes('//IDInfo') B(BatchXml)
WHERE A.BatchXml.exist('IDInfo/IDType[text()=3]')=1
AND B.BatchXml.exist('IDType[text()=3]')=1
這篇關于如何返回 SQL Server XPath 中存在的值?的文章就介紹到這了,希望我們推薦的答案對大家有所幫助,也希望大家多多支持html5模板網!