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    1. SQL - 使用 ID NOT IN 的高級重復(fù)刪除

      SQL - Advanced duplicates removal using ID NOT IN(SQL - 使用 ID NOT IN 的高級重復(fù)刪除)

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                本文介紹了SQL - 使用 ID NOT IN 的高級重復(fù)刪除的處理方法,對大家解決問題具有一定的參考價值,需要的朋友們下面隨著小編來一起學(xué)習(xí)吧!

                問題描述

                限時送ChatGPT賬號..

                我在我的表中發(fā)現(xiàn)了需要刪除的重復(fù)項.該表包含:

                I found duplicates in my table which needed to be removed. The table contains:

                1. ID - 表的唯一鍵
                2. STUDENT_ID - 學(xué)生的 ID
                3. SUBJECT_ID - 學(xué)生的科目
                4. CLASS_ID - 班級學(xué)生在
                5. XP_LVL - 專業(yè)水平

                一個學(xué)生應(yīng)該只有一個科目、班級和 XP_lvl 的記錄.在這種情況下,刪除重復(fù)項是基于刪除所有但保留一個.

                One student should have only one record of subject, class and XP_lvl. In this case the removal of duplicities is based on delete all but keep one.

                在我的情況下,重復(fù)看起來像這樣:

                In my case duplicates looks like this:

                <頭>
                IDSTUDENT_IDSUBJECT_IDCLASS_IDEXPERTISE_LVL
                11AAA55FFECLASS8082
                21AAA55FFECLASS8082
                32AAB49BBCLASS8903
                42AAB49BBCLASS8903
                52AAB49BBCLASS8904
                62AAB49BBCLASS8903

                我通過創(chuàng)建 (CONCAT(STUDENT_ID, CONCAT(SUBJECT_ID, CLASS_ID))) 的唯一 ID,然后通過 count.. >1 識別出所有重復(fù)項> 工作正常.

                I have identified all the duplicates by creating unique ID of (CONCAT(STUDENT_ID, CONCAT(SUBJECT_ID, CLASS_ID))) and then by having count.. >1 which works fine.

                現(xiàn)在我需要識別所有 ID,以便我可以在從查詢中刪除時使用 ID NOT IN (SELECT...).

                Now I need to identify all the ID so I can use ID NOT IN (SELECT...) in my delete from query.

                所以我這樣做了..

                AND ID NOT IN (SELECT UID FROM (
                SELECT
                    min(ID) AS UID,
                    STUDENT_ID,
                    SUBJECT_ID,
                    CLASS_ID    
                FROM
                    my_table 
                GROUP BY
                    STUDENT_ID,
                    SUBJECT_ID,
                    CLASS_ID    
                HAVING
                    count(CONCAT(STUDENT_ID, CONCAT(SUBJECT_ID, CLASS_ID))) > 1))
                

                但是,我不能使用 min/max(ID) 來選擇要保留的 ID,因為正如您所見,對于學(xué)生 2AAB,存在具有不同 XP_LVL 的重復(fù)項.

                However I cannot use min/max(ID) to choose which ID to keep because as you can see for student 2AAB there are duplicities with different XP_LVL.

                在這種情況下,我需要選擇最高 XP_LVL 的 ID 來保留和刪除所有其他的.

                In this case I need to select ID of highest XP_LVL to keep and delete all other.

                我嘗試使用 RANK、ROWNUM 不同的排序和子選擇的負(fù)載,但沒有想要的結(jié)果.

                I tried using RANK, ROWNUM different ordering and loaaads of subselects but without desired results.

                有誰知道如何有效地做到這一點?我們正在談?wù)?6k 重復(fù),所以我不能一一做.提前感謝您的幫助.

                Does anyone have any idea how to do it effectively ? We are talking about 6k duplicities so I cant do it one by one. Thank you for your help in advance.

                推薦答案

                您可以使用 ROW_NUMBER 解析函數(shù)并使用 ROWID 偽列關(guān)聯(lián)刪除:

                You can use ROW_NUMBER analytic function and correlate the deletion using the ROWID pseudo-column:

                DELETE FROM my_table
                WHERE ROWID IN (
                  SELECT ROWID
                  FROM   (
                    SELECT ROW_NUMBER() OVER (
                             PARTITION BY student_id, subject_id, class_id
                             ORDER BY expertise_lvl DESC
                           ) AS rn
                    FROM   my_table
                  )
                  WHERE  rn > 1
                )
                

                db<>fiddle 這里

                這篇關(guān)于SQL - 使用 ID NOT IN 的高級重復(fù)刪除的文章就介紹到這了,希望我們推薦的答案對大家有所幫助,也希望大家多多支持html5模板網(wǎng)!

                【網(wǎng)站聲明】本站部分內(nèi)容來源于互聯(lián)網(wǎng),旨在幫助大家更快的解決問題,如果有圖片或者內(nèi)容侵犯了您的權(quán)益,請聯(lián)系我們刪除處理,感謝您的支持!

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