問題描述

我需要將一對長度為 16 位的二進制序列存儲到一個字節數組(長度為 2)中.一個或兩個二進制數不會改變，因此進行轉換的函數可能是矯枉過正的.例如，16 位二進制序列是 1111000011110001.如何將其存儲在長度為 2 的字節數組中?

I need to store a couple binary sequences that are 16 bits in length into a byte array (of length 2). The one or two binary numbers don't change, so a function that does conversion might be overkill. Say for example the 16 bit binary sequence is 1111000011110001. How do I store that in a byte array of length two?

推薦答案

    String val = "1111000011110001";
    byte[] bval = new BigInteger(val, 2).toByteArray();

還有其他選擇，但我發現最好使用 BigInteger 類，它可以轉換為字節數組，來解決這類問題.我更喜歡 if，因為我可以從 String 實例化類，它可以表示各種基數，如 8、16 等，也可以這樣輸出.

There are other options, but I found it best to use BigInteger class, that has conversion to byte array, for this kind of problems. I prefer if, because I can instantiate class from String, that can represent various bases like 8, 16, etc. and also output it as such.

public static byte[] getRoger(String val) throws NumberFormatException,
        NullPointerException {
    byte[] result = new byte[2];
    byte[] holder = new BigInteger(val, 2).toByteArray();
    
    if (holder.length == 1) result[0] = holder[0];
    else if (holder.length > 1) {
        result[1] = holder[holder.length - 2];
        result[0] = holder[holder.length - 1];
    }
    return result;
}

例子:

int bitarray = 12321;
String val = Integer.toString(bitarray, 2);
System.out.println(new StringBuilder().append(bitarray).append(':').append(val)
  .append(':').append(Arrays.toString(getRoger(val))).append('
'));

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