問題描述

基本上，假設我有一個可以容納 10 個數字的 int 數組.這意味著我可以在每個索引中存儲 0-9(每個數字只能存儲一次).

Basically, let's say I have an int array that can hold 10 numbers. Which mean I can store 0-9 in each of the index (each number only once).

如果我運行下面的代碼:

If I run the code below:

int[] num = new int[10];
for(int i=0;i<10;i++){
    num[i]=i;
}

我的數組看起來像這樣:

my array would look like this:

[0],[1],.....,[8],[9]

但是如何在每次運行代碼時隨機分配數字?例如，我希望數組看起來像:

But how do I randomize the number assignment each time I run the code? For example, I want the array to look something like:

[8],[1],[0].....[6],[3]

推薦答案

將其設為 List 而不是數組，并使用 Collections.shuffle() 對其進行隨機播放.您可以在洗牌后從列表中構建 int[].

Make it a List<Integer> instead of an array, and use Collections.shuffle() to shuffle it. You can build the int[] from the List after shuffling.

如果你真的想直接進行隨機播放，請搜索Fisher-Yates Shuffle".

If you really want to do the shuffle directly, search for "Fisher-Yates Shuffle".

以下是使用列表技術的示例:

Here is an example of using the List technique:

import java.util.ArrayList;
import java.util.Collections;
import java.util.List;

public class Test {
  public static void main(String args[]) {
    List<Integer> dataList = new ArrayList<Integer>();
    for (int i = 0; i < 10; i++) {
      dataList.add(i);
    }
    Collections.shuffle(dataList);
    int[] num = new int[dataList.size()];
    for (int i = 0; i < dataList.size(); i++) {
      num[i] = dataList.get(i);
    }

    for (int i = 0; i < num.length; i++) {
      System.out.println(num[i]);
    }
  }
}

這篇關于如何在給定范圍內創建一個隨機打亂數字的 int 數組的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！