本文介紹了在 SELECT(MYSQL/PHP) 中加入 2 個(gè)表的處理方法，對(duì)大家解決問(wèn)題具有一定的參考價(jià)值，需要的朋友們下面隨著小編來(lái)一起學(xué)習(xí)吧！
問(wèn)題描述
我有這兩張桌子.連接密鑰"是兩個(gè)表中都包含的 conID.所以現(xiàn)在我想寫一個(gè) select 語(yǔ)句，它會(huì)給我這樣的東西:
I have these two tables. The connecting "key" is conID which is included in both tables. So now i would like to write select statement which would give me something like this:
John Smith 乳品 22 Texas 4000 smth4
John Smith dairy22 Texas 4000 smth4
Mike Situation glenn32 Jersey 1000 smth1...
Mike Situation glenn32 Jersey 1000 smth1 ...
>表人":
NUM Name lastName address conID
-----------------------------------------
1 John Smith dairy22 Texas
2 Mike Situation glenn32 Jersey
3 Duke Nukem haris48 NYork
4 Queen Lisa court84 London
>表國(guó)家"
conID postNum region
-------------------------
Jersey 1000 smth1
NYork 2000 smth2
London 3000 smth3
Texas 4000 smth4
<強(qiáng)>！-> NUM 是 AUTO INCREMENT 主鍵，如果可能的話，我不希望它是輸出.
提前感謝您的幫助:))
Thanks for help in advance :))
推薦答案
這應(yīng)該返回您想要的行，基于 num 列:
This should return the rows you want, based on the num column:
SELECT Name, lastName, address, people.conID, postNum, region
FROM people
JOIN countries
ON people.conID = countries.conID
WHERE num=1
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