問題描述
我想合并兩個數組:
$filtered = array(1 => 'a', 3 => 'c');
$changed = array(2 => 'b*', 3 => 'c*');
而合并應包括 $filtered 的所有元素和 $changed 的所有元素，這些元素在 $filtered 中有相應的鍵:
Whereas the merge should include all elements of $filtered and all those elements of $changed that have a corresponding key in $filtered:
$merged = array(1 => 'a', 3 => 'c*');
array_merge($filtered, $changed) 也會將 $changed 的附加鍵添加到 $filtered 中.所以不太合適.
array_merge($filtered, $changed) would add the additional keys of $changed into $filtered as well. So it does not really fit.
我知道我可以使用 $keys = array_intersect_key($filtered, $changed) 來獲取兩個數組中存在的鍵，這已經完成了一半的工作.
I know that I can use $keys = array_intersect_key($filtered, $changed) to get the keys that exist in both arrays which is already half of the work.
但是我想知道是否有任何(本機)函數可以將 $changed 數組減少為具有 array_intersect_key 指定的 $keys 的數組?我知道我可以使用帶有回調函數的 array_filter 并檢查其中的 $keys，但可能還有其他一些純本機函數來僅從數組中提取那些元素可以指定鍵嗎?
However I'm wondering if there is any (native) function that can reduce the $changed array into an array with the $keys specified by array_intersect_key? I know I can use array_filter with a callback function and check against $keys therein, but there is probably some other purely native function to extract only those elements from an array of which the keys can be specified?
我這么問是因為原生函數通常比帶有回調的 array_filter 快得多.
I'm asking because the native functions are often much faster than array_filter with a callback.
推薦答案
如果我正確理解你的邏輯，應該這樣做:
This should do it, if I'm understanding your logic correctly:
array_intersect_key($changed, $filtered) + $filtered
<小時>
實施:
$filtered = array(1 => 'a', 3 => 'c');
$changed = array(2 => 'b*', 3 => 'c*');
$expected = array(1 => 'a', 3 => 'c*');
$actual = array_key_merge_deceze($filtered, $changed);
var_dump($expected, $actual);
function array_key_merge_deceze($filtered, $changed) {
$merged = array_intersect_key($changed, $filtered) + $filtered;
ksort($merged);
return $merged;
}
輸出:
Expected:
array(2) {
[1]=>
string(1) "a"
[3]=>
string(2) "c*"
}
Actual:
array(2) {
[1]=>
string(1) "a"
[3]=>
string(2) "c*"
}
這篇關于如何通過僅從與第一個數組具有相同鍵的第二個數組中接管值來合并兩個數組?的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！