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      使用 mysqli 獲取行

      Fetch rows using mysqli(使用 mysqli 獲取行)
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                本文介紹了使用 mysqli 獲取行的處理方法,對(duì)大家解決問題具有一定的參考價(jià)值,需要的朋友們下面隨著小編來一起學(xué)習(xí)吧!

                問題描述

                這是一個(gè)簡(jiǎn)單的代碼.每次上傳文件時(shí),我都想在數(shù)據(jù)庫中保留一條記錄.每次上傳任何文件時(shí),我都希望用戶從數(shù)據(jù)庫中以串行方式查看他/她的所有上傳文件.上傳文件時(shí)的記錄保存工作正常.但是在獲取包含所有上傳文件信息的表時(shí)出現(xiàn)問題.

                its a simple code. I want to keep a record in the database each time when a file is being uploaded. And when each time any file is being uploaded I want the user to see he/her's all uploaded files in a serial from the database. The record keeping while uploading file works fine. But the problem appears while fetching the table containing all the uploaded file information.

                //connetion code 
                $con = mysqli_connect("localhost", "root", "", "sss");
                
                if (mysqli_connect_errno()) 
                {
                    printf("Connect failed: %s
                ", mysqli_connect_error());
                    exit();
                }
                
                //file upload code
                move_uploaded_file($_FILES["file"]["tmp_name"],"C:/xampp/htdocs/" . $_FILES["file"]["name"]);
                mysqli_query($con, "INSERT INTO uploads ( filename, uploaded_on) VALUES ( '{$_FILES['file']['name']}', NOW());");
                echo "Stored in: " . "C:/xampp/htdocs/" . $_FILES["file"]["name"];
                
                //fetch rows 
                $result =mysqli_query($con, "select * from uploads");
                
                while ($row = mysqli_fetch_array($result))
                {
                    printf ("%s
                ", $row);
                }
                
                mysqli_close($con);
                }
                

                我能感覺到編碼存在一些嚴(yán)重的問題.這是我第一次在 mysqli 中工作,之前我曾經(jīng)使用 mysql 進(jìn)行編碼.需要幫助以了解實(shí)際問題和解決方案.

                I can feel that there are some serious problem in coding. This is my first time working in mysqli, before I used to code using mysql. need help to know the actual problem and the solution.

                它返回這個(gè),

                Notice: Array to string conversion in C:xampphtdocssssupload_file.php on line 68
                Array
                
                Notice: Array to string conversion in C:xampphtdocssssupload_file.php on line 68
                Array
                
                Notice: Array to string conversion in C:xampphtdocssssupload_file.php on line 68
                Array
                

                但不幸的是,這段代碼是龐大代碼的一部分.所以這里的第 68 行是 $result = mysqli_query($con, "select * from uploads"); 開始的那一行.

                but unfortunately this code is a part of a huge code. so here line 68 is the line where the $result = mysqli_query($con, "select * from uploads"); starts.

                推薦答案

                $result =mysqli_query($con, "select * from uploads");
                while ($row = mysqli_fetch_assoc($result))
                   {
                      printf ("%s
                ", $row['column_name_1']);
                      printf ("%s
                ", $row['column_name_2']);
                      printf ("%s
                ", $row['column_name_3']);
                   }
                mysqli_close($con);
                

                但是您應(yīng)該認(rèn)真考慮查看代碼的安全性.

                But you should seriously consider looking at the security of your code.

                這篇關(guān)于使用 mysqli 獲取行的文章就介紹到這了,希望我們推薦的答案對(duì)大家有所幫助,也希望大家多多支持html5模板網(wǎng)!

                【網(wǎng)站聲明】本站部分內(nèi)容來源于互聯(lián)網(wǎng),旨在幫助大家更快的解決問題,如果有圖片或者內(nèi)容侵犯了您的權(quán)益,請(qǐng)聯(lián)系我們刪除處理,感謝您的支持!

                相關(guān)文檔推薦

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