本文介紹了如何在 PHP 中運行 bind_param() 語句?的處理方法,對大家解決問題具有一定的參考價值,需要的朋友們下面隨著小編來一起學習吧!
問題描述
我正在嘗試使以下代碼工作,但無法到達 execute()
行.
I'm trying to make the following code work but I can't reach the execute()
line.
$mysqli = $this->ConnectLowPrivileges();
echo 'Connected<br>';
$stmt = $mysqli->prepare("SELECT `name`, `lastname` FROM `tblStudents` WHERE `idStudent`=?");
echo 'Prepared and binding parameters<br>';
$stmt->bind_param('i', 2 );
echo 'Ready to execute<br>'
if ($stmt->execute()){
echo 'Executing..';
}
} else {
echo 'Error executing!';
}
mysqli_close($mysqli);
我得到的輸出是:
Connected
Prepared and binding parameters
所以問題應該在第 5 行,但檢查 bind_param()
手冊我在那里找不到任何語法錯誤.
So the problem should be at line 5, but checking the manual of bind_param()
I can't find any syntax error there.
推薦答案
綁定參數時需要傳遞一個變量作為引用:
When binding parameters you need to pass a variable that is used as a reference:
$var = 1;
$stmt->bind_param('i', $var);
參見手冊:http://php.net/manual/en/mysqli-stmt.bind-param.php
注意 $var
實際上并不需要定義來綁定它.以下是完全有效的:
Note that $var
doesn't actually have to be defined to bind it. The following is perfectly valid:
$stmt->bind_param('i', $var);
foreach ($array as $element)
{
$var = $element['foo'];
$stmt->execute();
}
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