問題描述
如何在 Python 中將二進制字符串轉換為對應的十六進制值?
我有 0000 0100 1000 1101 我想獲得 048D 我正在使用 Python 2.6.
int 給定 base 2 然后 hex:
>>>整數('010110'，2)22>>>十六進制(整數('010110'，2))'0x16'>>>>>>十六進制(整數('0000010010001101'，2))'0x48d'int的文檔:
int(x[, base]) ->整數如果可能，將字符串或數字轉換為整數.一個漂浮的點參數將被截斷為零(這不包括字符串浮點數的表示！)轉換字符串時，利用可選基地.轉換 a 時提供堿基是錯誤的非字符串.如果基數為零，則根據字符串內容.如果參數超出整數范圍將改為返回長對象.
hex的文檔:
十六進制(數字)->細繩返回整數或長整數的十六進制表示整數.
How can I perform a conversion of a binary string to the corresponding hex value in Python?
I have 0000 0100 1000 1101 and I want to get 048D I'm using Python 2.6.
int given base 2 and then hex:
>>> int('010110', 2)
22
>>> hex(int('010110', 2))
'0x16'
>>>
>>> hex(int('0000010010001101', 2))
'0x48d'
The doc of int:
int(x[, base]) -> integer Convert a string or number to an integer, if possible. A floatingpoint argument will be truncated towards zero (this does not include a string representation of a floating point number!) When converting a string, use the optional base. It is an error to supply a base when converting a non-string. If base is zero, the proper base is guessed based on the string content. If the argument is outside the integer range a long object will be returned instead.
The doc of hex:
hex(number) -> string Return the hexadecimal representation of an integer or longinteger.
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