問題描述

goodreads 網站有這個 API 用于訪問用戶的貨架":https://www.goodreads.com/review/list/20990068.xml?key=nGvCqaQ6tn9w4HNpW8kquw&v=2&shelf=toread

The goodreads website has this API for accessing a user's 'shelves:' https://www.goodreads.com/review/list/20990068.xml?key=nGvCqaQ6tn9w4HNpW8kquw&v=2&shelf=toread

它返回 XML.我正在嘗試創建一個 django 項目，該項目在此 API 的書架上顯示書籍.我正在尋找如何(或者是否有更好的方法)來編寫我的視圖，以便我可以將對象傳遞給我的模板.目前，這就是我正在做的事情:

It returns XML. I'm trying to create a django project that shows books on a shelf from this API. I'm looking to find out how (or if there is a better way than) to write my view so I can pass an object to my template. Currently, this is what I'm doing:

import urllib2

def homepage(request):
    file = urllib2.urlopen('https://www.goodreads.com/review/list/20990068.xml?key=nGvCqaQ6tn9w4HNpW8kquw&v=2&shelf=toread')
    data = file.read()
    file.close()
    dom = parseString(data)

如果我正確執行此操作，我不完全確定如何操作此對象.我正在關注這個教程.

I'm not entirely sure how to manipulate this object if I'm doing this correctly. I'm following this tutorial.

推薦答案

我會使用 xmltodict 從 XML 數據結構中創建一個 python 字典，并將這個字典傳遞給上下文中的模板:

I'd use xmltodict to make a python dictionary out of the XML data structure and pass this dictionary to the template inside the context:

import urllib2
import xmltodict

def homepage(request):
    file = urllib2.urlopen('https://www.goodreads.com/review/list/20990068.xml?key=nGvCqaQ6tn9w4HNpW8kquw&v=2&shelf=toread')
    data = file.read()
    file.close()

    data = xmltodict.parse(data)
    return render_to_response('my_template.html', {'data': data})

這篇關于將 XML 從 URL 解析為 python 對象的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！