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問題描述
如果我在線程完成后再次嘗試運行線程，我試圖弄清楚為什么這段代碼會崩潰.
I am trying to figure out why this code crashes if I try to run the threads for a second time once they are completed.
我第一次單擊開始 5 個線程"時，它運行得很好并完成了.但如果我再次點擊它.整個程序崩潰，我得到 QThread: Destroyed while thread is still running Error
The first time I click "Start 5 Threads" It runs just fine and finishes. But if I click it again. The entire program crashes and I get the QThread: Destroyed while thread is still running Error
此代碼是在網絡上找到的.我正在努力學習.
This code was found on the web. I am trying to learn from it.
import time
import sys
from PyQt5.QtCore import QObject, QThread, pyqtSignal, pyqtSlot
from PyQt5.QtWidgets import QApplication, QPushButton, QTextEdit, QVBoxLayout, QWidget
def trap_exc_during_debug(*args):
# when app raises uncaught exception, print info
print(args)
# install exception hook: without this, uncaught exception would cause application to exit
sys.excepthook = trap_exc_during_debug
class Worker(QObject):
"""
Must derive from QObject in order to emit signals, connect slots to other signals, and operate in a QThread.
"""
sig_step = pyqtSignal(int, str) # worker id, step description: emitted every step through work() loop
sig_done = pyqtSignal(int) # worker id: emitted at end of work()
sig_msg = pyqtSignal(str) # message to be shown to user
def __init__(self, id: int):
super().__init__()
self.__id = id
self.__abort = False
@pyqtSlot()
def work(self):
"""
Pretend this worker method does work that takes a long time. During this time, the thread's
event loop is blocked, except if the application's processEvents() is called: this gives every
thread (incl. main) a chance to process events, which in this sample means processing signals
received from GUI (such as abort).
"""
thread_name = QThread.currentThread().objectName()
thread_id = int(QThread.currentThreadId()) # cast to int() is necessary
self.sig_msg.emit('Running worker #{} from thread "{}" (#{})'.format(self.__id, thread_name, thread_id))
for step in range(100):
time.sleep(0.1)
self.sig_step.emit(self.__id, 'step ' + str(step))
# check if we need to abort the loop; need to process events to receive signals;
app.processEvents() # this could cause change to self.__abort
if self.__abort:
# note that "step" value will not necessarily be same for every thread
self.sig_msg.emit('Worker #{} aborting work at step {}'.format(self.__id, step))
break
self.sig_done.emit(self.__id)
def abort(self):
self.sig_msg.emit('Worker #{} notified to abort'.format(self.__id))
self.__abort = True
class MyWidget(QWidget):
NUM_THREADS = 5
# sig_start = pyqtSignal() # needed only due to PyCharm debugger bug (!)
sig_abort_workers = pyqtSignal()
def __init__(self):
super().__init__()
self.setWindowTitle("Thread Example")
form_layout = QVBoxLayout()
self.setLayout(form_layout)
self.resize(400, 800)
self.button_start_threads = QPushButton()
self.button_start_threads.clicked.connect(self.start_threads)
self.button_start_threads.setText("Start {} threads".format(self.NUM_THREADS))
form_layout.addWidget(self.button_start_threads)
self.button_stop_threads = QPushButton()
self.button_stop_threads.clicked.connect(self.abort_workers)
self.button_stop_threads.setText("Stop threads")
self.button_stop_threads.setDisabled(True)
form_layout.addWidget(self.button_stop_threads)
self.log = QTextEdit()
form_layout.addWidget(self.log)
self.progress = QTextEdit()
form_layout.addWidget(self.progress)
QThread.currentThread().setObjectName('main') # threads can be named, useful for log output
self.__workers_done = None
self.__threads = None
def start_threads(self):
self.log.append('starting {} threads'.format(self.NUM_THREADS))
self.button_start_threads.setDisabled(True)
self.button_stop_threads.setEnabled(True)
self.__workers_done = 0
self.__threads = []
for idx in range(self.NUM_THREADS):
worker = Worker(idx)
thread = QThread()
thread.setObjectName('thread_' + str(idx))
self.__threads.append((thread, worker)) # need to store worker too otherwise will be gc'd
worker.moveToThread(thread)
# get progress messages from worker:
worker.sig_step.connect(self.on_worker_step)
worker.sig_done.connect(self.on_worker_done)
worker.sig_msg.connect(self.log.append)
# control worker:
self.sig_abort_workers.connect(worker.abort)
# get read to start worker:
# self.sig_start.connect(worker.work) # needed due to PyCharm debugger bug (!); comment out next line
thread.started.connect(worker.work)
thread.start() # this will emit 'started' and start thread's event loop
# self.sig_start.emit() # needed due to PyCharm debugger bug (!)
@pyqtSlot(int, str)
def on_worker_step(self, worker_id: int, data: str):
self.log.append('Worker #{}: {}'.format(worker_id, data))
self.progress.append('{}: {}'.format(worker_id, data))
@pyqtSlot(int)
def on_worker_done(self, worker_id):
self.log.append('worker #{} done'.format(worker_id))
self.progress.append('-- Worker {} DONE'.format(worker_id))
self.__workers_done += 1
if self.__workers_done == self.NUM_THREADS:
self.log.append('No more workers active')
self.button_start_threads.setEnabled(True)
self.button_stop_threads.setDisabled(True)
# self.__threads = None
@pyqtSlot()
def abort_workers(self):
self.sig_abort_workers.emit()
self.log.append('Asking each worker to abort')
for thread, worker in self.__threads: # note nice unpacking by Python, avoids indexing
thread.quit() # this will quit **as soon as thread event loop unblocks**
thread.wait() # <- so you need to wait for it to *actually* quit
# even though threads have exited, there may still be messages on the main thread's
# queue (messages that threads emitted before the abort):
self.log.append('All threads exited')
if __name__ == "__main__":
app = QApplication([])
form = MyWidget()
form.show()
sys.exit(app.exec_())
推薦答案
通過將他作為父母傳遞給自己來解決問題.你必須改變:
The problem is solved by passing him as a parent to self. You must change:
thread = QThread()
到:
thread = QThread(parent=self)
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