問題描述
我寫了以下課程:
class myClass(object):
def __init__(self):
pass
def foo(self, arg1, arg2):
pp = foobar(self, arg1, arg2)
if pp:
return 42
else
return -666
def foobar(self, arg1, arg2):
if arg1 == arg2:
return 42
else:
return None
邏輯是荒謬的 - 忽略它.我試圖這樣做是從另一個實例方法調用一個實例方法 - 我得到一個 NameError.我最初認為這是由于 foo() 在定義之前調用了 foobar() - 但是在腳本中切換函數定義的順序沒有任何區別.
The logic is nonsensical - ignore it. What I am trying to so is to call an instance method from another instance method - and I am getting a NameError. I originally thought that this was due to foo() calling foobar() before it had been defined - but switching the order of the function definitions in the script made no difference.
有沒有人知道是什么導致了這個錯誤，以及如何解決它?
Does anyone what's causing this error, and how to fix it?
推薦答案
Python 不會自動將代碼范圍限定為本地類；你需要告訴它.
Python doesn't scope code to the local class automatically; you need to tell it to.
pp = self.foobar(arg1, arg2)
http://docs.python.org/tutorial/classes.html
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