問題描述

我可以從同名函數調用全局函數嗎?

Can I call a global function from a function that has the same name?

例如:

def sorted(services):
    return {sorted}(services, key=lambda s: s.sortkey())

{sorted} 我的意思是全局排序函數.有沒有辦法做到這一點?然后我想用模塊名稱調用我的函數:service.sorted(services)

By {sorted} I mean the global sorted function. Is there a way to do this? I then want to call my function with the module name: service.sorted(services)

我想使用相同的名稱，因為它與全局函數做同樣的事情，只是它添加了一個默認參數.

I want to use the same name, because it does the same thing as the global function, except that it adds a default argument.

推薦答案

Python 的名稱解析方案有時被稱為 LEGB 規則，這意味著當您在函數中使用非限定名稱時，Python 最多搜索四個范圍——首先本地 (L) 范圍，然后是任何封閉 (E) def 和 lambda 的本地范圍s，然后是全局 (G) 范圍，最后是內置 (B) 范圍.(請注意，一旦找到匹配項，它將立即停止搜索)

Python's name-resolution scheme which sometimes is referred to as LEGB rule, implies that when you use an unqualified name inside a function, Python searches up to four scopes— First the local (L) scope, then the local scopes of any enclosing (E) defs and lambdas, then the global (G) scope, and finally the built-in (B) scope. (Note that it will stops the search as soon as it finds a match)

因此，當您在函數解釋器中使用 sorted 時，會將其視為 全局 名稱(您的函數名稱)，因此您將擁有一個遞歸函數.如果你想訪問內置的 sorted 你需要為 Python 指定它.通過 __builtin__ 模塊(在 Python-2.x 中)和 builtins 在 Python-3.x 中(此模塊提供對 Python 的所有內置"標識符的直接訪問)

So when you use sorted inside the functions interpreter considers it as a Global name (your function name) so you will have a recursion function. if you want to access to built-in sorted you need to specify that for Python . by __builtin__ module (in Python-2.x ) and builtins in Python-3.x (This module provides direct access to all ‘built-in’ identifiers of Python)

蟒蛇2:

import __builtin__
def sorted(services):
    return __builtin__.sorted(services, key=lambda s: s.sortkey())

蟒蛇3:

import builtins
def sorted(services):
    return builtins.sorted(services, key=lambda s: s.sortkey())

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