問題描述
我希望 for 循環(huán)中的迭代器變量作為 unsigned int 反向迭代到 0，我想不出與 i > 類似的比較.-1，就像如果它是 signed int 一樣.
I want the iterator variable in a for loop to reverse iterate to 0 as an unsigned int, and I cannot think of a similar comparison to i > -1, as you would do if it was a signed int.
for (unsigned int i = 10; i <= 10; --i) { ... }
但這似乎很不清楚，因?yàn)樗蕾囉跓o符號(hào)整數(shù)的數(shù)值溢出超過 10.
But this seems very unclear, as it is relying on the numerical overflow of the unsigned integer to be above 10.
也許我只是沒有清醒的頭腦，但有什么更好的方法可以做到這一點(diǎn)...
Maybe I just don't have a clear head, but whats a better way to do this...
免責(zé)聲明:這只是一個(gè)簡(jiǎn)單的用例，10 的上限是微不足道的，它可以是任何東西，并且 i 必須是一個(gè) unsigned int.
Disclaimer: this is just a simple use case, the upper limit of 10 is trivial, it could be anything, and i must be an unsigned int.
推薦答案
可以使用
for( unsigned int j = n; j-- > 0; ) { /*...*/ }
它從 n-1 向下迭代到 0.
It iterates from n-1 down to 0.
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