問題描述
我知道它是一個整數類型，可以在不丟失數據的情況下轉換為/從指針轉換，但我為什么要這樣做呢?與 void* 用于保存指針和 THE_REAL_TYPE*?? 用于指針運算相比，整數類型有什么優勢?
I know it is an integer type that can be cast to/from pointer without loss of data, but why would I ever want to do this? What advantage does having an integer type have over void* for holding the pointer and THE_REAL_TYPE* for pointer arithmetic?
編輯
標記為已經被問過"的問題不回答這個.問題是使用 intptr_t 作為 void* 的一般替代品是否是一個好主意，并且那里的答案似乎是不要使用 intptr_t"，所以我的問題仍然有效:intptr_t 的一個好的用例是什么?
EDIT
The question marked as "already been asked" doesn't answer this. The question there is if using intptr_t as a general replacement for void* is a good idea, and the answers there seem to be "don't use intptr_t", so my question is still valid: What would be a good use case for intptr_t?
推薦答案
主要原因，你不能對 void * 進行按位運算，但你可以對 intptr_t 做同樣的操作.
The primary reason, you cannot do bitwise operation on a void *, but you can do the same on a intptr_t.
在許多需要對地址執行按位運算的場合，可以使用intptr_t.
On many occassion, where you need to perform bitwise operation on an address, you can use intptr_t.
然而，對于按位運算，最好的方法是使用 unsigned 對應物，uintptr_t.
However, for bitwise operations, best approach is to use the unsigned counterpart, uintptr_t.
如 其他答案中所述，@chux，指針比較是另一個重要方面.
As mentioned in the other answer by @chux, pointer comparison is another important aspect.
此外，FWIW，根據 C11 標準，§7.20.1.4，
Also, FWIW, as per C11 standard, §7.20.1.4,
這些類型是可選的.
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