本文介紹了SQL Server 用戶定義函數來計算年齡段的處理方法,對大家解決問題具有一定的參考價值,需要的朋友們下面隨著小編來一起學習吧!
問題描述
我創建了一個 UDF 來計算數據庫中的年齡段.我使用了以下代碼
I created a UDF to calculate age bracket in the database. i used the following codes
CREATE FUNCTION Agebracket(@Ages INT)
RETURNS VARCHAR
AS
BEGIN
DECLARE @Age_Group varchar
SET @Age_Group = CASE WHEN @Ages BETWEEN 0 AND 9 THEN '[0-9]'
WHEN @Ages BETWEEN 10 AND 19 THEN '[10-19]'
WHEN @Ages BETWEEN 20 AND 29 THEN '[20-29]'
WHEN @Ages BETWEEN 30 AND 39 THEN '[30-39]'
WHEN @Ages BETWEEN 40 AND 49 THEN '[40-49]'
WHEN @Ages BETWEEN 50 AND 59 THEN '[50-59]'
WHEN @Ages BETWEEN 60 AND 69 THEN '[60-69]'
WHEN @Ages BETWEEN 70 AND 79 THEN '[70-79]'
WHEN @Ages BETWEEN 80 AND 89 THEN '[80-89]'
WHEN @Ages BETWEEN 90 AND 99 THEN '[90-99]'
WHEN @Ages>=100 THEN '[100+]' end
RETURN @Age_Group
END
當我用下面的例子進行測試時:
when i test with the example below:
SELECT [dbo].[Agebracket](10)
輸出為 [
.
關于我可以做什么的任何想法,因為我希望輸出為 [10-19]
Any idea on what i can do as i expect the output to be [10-19]
推薦答案
用 DECLARE @Age_Group varchar(8)
替換 DECLARE @Age_Group varchar
并使你的函數成為返回 varchar(8)
.
Replace DECLARE @Age_Group varchar
with DECLARE @Age_Group varchar(8)
and also make your function to return varchar(8)
.
工作版本:
alter FUNCTION Agebracket(@Ages INT)
RETURNS VARCHAR(8)
AS
BEGIN
DECLARE @Age_Group varchar(8)
SET @Age_Group = CASE WHEN @Ages BETWEEN 0 AND 9 THEN '[0-9]'
WHEN @Ages BETWEEN 10 AND 19 THEN '[10-19]'
WHEN @Ages BETWEEN 20 AND 29 THEN '[20-29]'
WHEN @Ages BETWEEN 30 AND 39 THEN '[30-39]'
WHEN @Ages BETWEEN 40 AND 49 THEN '[40-49]'
WHEN @Ages BETWEEN 50 AND 59 THEN '[50-59]'
WHEN @Ages BETWEEN 60 AND 69 THEN '[60-69]'
WHEN @Ages BETWEEN 70 AND 79 THEN '[70-79]'
WHEN @Ages BETWEEN 80 AND 89 THEN '[80-89]'
WHEN @Ages BETWEEN 90 AND 99 THEN '[90-99]'
WHEN @Ages>=100 THEN '[100+]' end
RETURN @Age_Group
END
GO
SELECT [dbo].[Agebracket](10)
這是因為 SQL Server 假定 VARCHAR = VARCHAR(1),更糟糕的是,它會以靜默方式截斷值.
This is because SQL Server assumes VARCHAR = VARCHAR(1) and even worse, it will silently truncate the values.
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