本文介紹了SQL 計算所有行而不是計算單個行的處理方法,對大家解決問題具有一定的參考價值,需要的朋友們下面隨著小編來一起學習吧!
問題描述
我有一個從數據庫請求數據的 SQL 語句.
I have a SQL statement which requests data from the database.
SELECT `ID`, `To`, `Poster`, `Content`, `Time`, ifnull(`Aura`,0) as `Aura` FROM (
SELECT * FROM (
SELECT DISTINCT * FROM messages m
INNER JOIN
(
SELECT Friend2 as Friend FROM friends WHERE Friend1 = '1'
UNION ALL
SELECT Friend1 as Friend FROM friends WHERE Friend2 = '1'
) friends ON m.Poster = friends.`Friend`
UNION ALL SELECT DISTINCT *, '1' FROM messages where `Poster`='1'
) var
LEFT JOIN
(
select `ID` as `AuraID`, `Status` as `AuraStatus`, count(*) as `Aura`
from messages_aura
) aura ON (var.Poster = aura.AuraID AND var.ID = aura.AuraStatus)
) final
GROUP BY `ID`, `Poster`
ORDER BY `Time` DESC LIMIT 10
這是我的 messages_aura
表格布局.它顯示 ID
、Status
和 UserID
.
Here is my messages_aura
table layout. It shows ID
, Status
and UserID
.
這是上述語句的輸出.
(上面截圖中的ID
指的是下面的Poster
,上面截圖中的Status
指的是ID
代碼> 下面)
(The ID
from the above screenshot refers to Poster
below and the Status
from the above screenshot refers to ID
below)
該語句應為底行提供 1
的 Aura 計數,并為頂行提供 2
的 Aura 計數.怎么了?
The statement should give the bottom row a Aura count of 1
and the top row an Aura count of 2
. What's wrong?
推薦答案
您缺少 GROUP BY
,因此它會計算所有內容,而不是按某些列分組.
You're missing GROUP BY
, so it's counting everything instead of grouping by some columns.
LEFT JOIN
(
select `ID` as `AuraID`, `Status` as `AuraStatus`, count(*) as `Aura`
from messages_aura
GROUP BY AuraID, AuraStatus
) aura ON (var.Poster = aura.AuraID AND var.ID = aura.AuraStatus)
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