問題描述
我從 http://www.movable-type.co.uk 實現了軸承"公式/scripts/latlong.html.但這似乎非常不準確 - 我懷疑我的實施中有一些錯誤.你能幫我找到它嗎?我的代碼如下:
I implemented the "bearing" formula from http://www.movable-type.co.uk/scripts/latlong.html. But it seems highly inaccurate - I suspect some mistakes in my implementation. Could you help me with finding it? My code is below:
protected static double bearing(double lat1, double lon1, double lat2, double lon2){
double longDiff= lon2-lon1;
double y = Math.sin(longDiff)*Math.cos(lat2);
double x = Math.cos(lat1)*Math.sin(lat2)-Math.sin(lat1)*Math.cos(lat2)*Math.cos(longDiff);
return Math.toDegrees((Math.atan2(y, x))+360)%360;
}
推薦答案
你只是把括號 () 放錯地方了.
You just have your parentheses () in the wrong place.
您正在為弧度值添加度數，這不起作用.toDegrees() 將為您完成從弧度到度數的轉換，然后一旦您有度數的值，您就可以進行標準化.
You are adding degrees to a value in radians, which won't work. toDegrees() will do the conversion from radians to degrees for you, then you do the normalisation once you have a value in degrees.
你有:
Math.toDegrees( (Math.atan2(y, x))+360 ) % 360;
但你需要:
( Math.toDegrees(Math.atan2(y, x)) + 360 ) % 360;
還請記住，Math.sin()、Math.cos() 和所有其他三角函數的所有輸入都必須以弧度表示.如果您的輸入是度數，您需要先使用 Math.toRadians() 進行轉換.
Remember also that all inputs to Math.sin(), Math.cos() and all the other trigonometric functions must be in radians. If your inputs are degrees you'll need to convert them using Math.toRadians() first.
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