本文介紹了Integer.parseInt(String str) java.lang.NumberFormatException: 錯誤的處理方法，對大家解決問題具有一定的參考價值，需要的朋友們下面隨著小編來一起學習吧！
問題描述
I keep getting number format expectations, even though I'm trimming the strings and they don't contain non numerical characters bizarrely it works for some numbers and not others. Below is an example of a string I get number format exception for. Also, any string starting with 0 e.g "0208405223", is returned 208405223, there's no zero anymore is that supposed to happen?
String n="3020857508";
Integer a = Integer.parseInt(n.trim());
System.out.println(a);
This is the exception:
Exception in thread "main" java.lang.NumberFormatException: For input string: "3020857508"
at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
at java.lang.Integer.parseInt(Integer.java:583)
at java.lang.Integer.parseInt(Integer.java:615)
at JavaBeans.Main.main(Main.java:15)
解決方案
It's because 3020857508 exceeds Integer.MAX_VALUE. You should use long to convert the string to number.
java> String n="3020857508";
//=> java.lang.String n = "3020857508"
java> Integer a = Integer.parseInt(n.trim());
//=> java.lang.NumberFormatException: For input string: "3020857508"
java> Integer.MAX_VALUE
//=> java.lang.Integer res2 = 2147483647
java> Long a = Long.parseLong(n.trim());
//=>java.lang.Long a = 3020857508
The above is javarepl output.
If you are using JDK9 or above, you can see the same result in jshell.
jshell> String n="3020857508"
n ==> "3020857508"
jshell> Integer a = Integer.parseInt(n.trim())
| Exception java.lang.NumberFormatException: For input string: "3020857508"
| at NumberFormatException.forInputString (NumberFormatException.java:65)
| at Integer.parseInt (Integer.java:652)
| at Integer.parseInt (Integer.java:770)
| at (#2:1)
jshell> Integer.MAX_VALUE
$3 ==> 2147483647
jshell> Long a = Long.parseLong(n.trim());
a ==> 3020857508
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