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本文介紹了圍繞點(diǎn)旋轉(zhuǎn)三角形java的處理方法，對(duì)大家解決問(wèn)題具有一定的參考價(jià)值，需要的朋友們下面隨著小編來(lái)一起學(xué)習(xí)吧！

問(wèn)題描述

我遇到了麻煩.我需要使用拖動(dòng)偵聽(tīng)器和單擊偵聽(tīng)器圍繞其中心旋轉(zhuǎn)等邊三角形.三角形應(yīng)該會(huì)增長(zhǎng)，但現(xiàn)在會(huì)改變角度并旋轉(zhuǎn)一個(gè)點(diǎn)，同時(shí)以三角形的中間為中心.這是我的問(wèn)題，它目前正在拖動(dòng)點(diǎn) 3 并圍繞點(diǎn) 1 旋轉(zhuǎn).我有一個(gè)值 x 和 y 的數(shù)組，它存儲(chǔ) 4 個(gè)值，每個(gè)值首先在序數(shù)值 0 處包含初始點(diǎn)，在點(diǎn) 1 2 和 3 處對(duì)應(yīng)的值.

I am having trouble. I need to rotate an equilateral triangle around it's centre by using the drag listener and click listener. The triangle should grow but now change angles and be rotated by a point while being centred at the middle of the triangle. This is my problem, it is currently dragging by the point 3 and rotating around point 1. I have an array of values x and y and it stores 4 values each containing the initial point first at ordinal value 0 and point 1 2 and 3 at the corresponding values.

public class DrawTriangle extends JFrame {

enter code here
/** The Constant NUMBER_3. */
private static final int NUMBER_3 = 3;

/** The Constant EQUL_ANGLE. */
@SuppressWarnings("unused")
private static final double EQUL_ANGLE = 1;

/** The Constant TRIANGLE_POINTS. */
private static final int TRIANGLE_POINTS = 4;

/** The Constant _400. */
private static final int SIZE = 400;

/** The x points. */
private int [] xPoints = new int[TRIANGLE_POINTS];

/** The y points. */
private int [] yPoints = new int[TRIANGLE_POINTS];

private int xInitial;

private int yInitial;

/** The x. */
private double x = EQUL_ANGLE;

/** The new x. */
private double newX;

/** The new y. */
private double newY;

/**
 * Instantiates a new draw triangle.
 */
public DrawTriangle() {
    super("Dimitry Rakhlei");
    setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    setContentPane(new DrawTrianglePanel());
    setSize(SIZE, SIZE); // you can change this size but don't make it HUGE!
    setVisible(true);
}

/**
 * The Class DrawTrianglePanel.
 */
private class DrawTrianglePanel extends JPanel implements MouseListener,
        MouseMotionListener {

    /**
     * Instantiates a new draw triangle panel.
     */
    public DrawTrianglePanel() {
        addMouseListener(this);
        addMouseMotionListener(this);
    }

    /**
     * Drawing the triangle.
     *
     * @param g
     *            the g
     * @see javax.swing.JComponent#paintComponent(java.awt.Graphics)
     */
    public void paintComponent(Graphics g) {
        super.paintComponent(g);
        // DRAWING CODE HERE
        g.drawPolygon(xPoints, yPoints, 3);
        System.out.println("Paint called");
    }



    /**
     * (non-Javadoc).
     *
     * @param e
     *            the e
     * @see java.awt.event.MouseListener#mousePressed
     * (java.awt.event.MouseEvent)
     */
    public void mousePressed(MouseEvent e) {
        System.out.println("Mouse pressed called");
        e.getPoint();
        xPoints[0] = e.getPoint().x;
        yPoints[0] = e.getPoint().y;
        repaint();

    }

    /**
     * (non-Javadoc).
     *
     * @param e
     *            the e
     * @see java.awt.event.MouseListener#mouseReleased
     * (java.awt.event.MouseEvent)
     */
    public void mouseReleased(MouseEvent e) {
        System.out.println("Mouse released called");
    }

    /**
     * (non-Javadoc).
     *
     * @param e
     *            the e
     * @see java.awt.event.MouseMotionListener#mouseDragged
     * (java.awt.event.MouseEvent)
     */
    public void mouseDragged(MouseEvent e) {
        System.out.println("Mouse dragged called");
        newX = e.getPoint().x;
        newY = e.getPoint().y;
        xPoints[1] = (int) newX;
        yPoints[1] = (int) newY;


        newX = xPoints[0] + (xPoints[1]-xPoints[0])*Math.cos(x) - (yPoints[1]-yPoints[0])*Math.sin(x);

        newY = yPoints[0] + (xPoints[1]-xPoints[0])*Math.sin(x) + (yPoints[1]-yPoints[0])*Math.cos(x);

        xPoints[2] = (int) newX;
        yPoints[2] = (int) newY;

        newX = xPoints[0] + (xPoints[1]-xPoints[0])*Math.cos(x) - (yPoints[1]-yPoints[0])*Math.sin(x);

        newY = yPoints[0] + (xPoints[1]-xPoints[0])*Math.sin(x) + (yPoints[1]-yPoints[0])*Math.cos(x);

        xPoints[3] = (int) newX;
        yPoints[3] = (int) newY;

        repaint();
    }

    /**
     * (non-Javadoc).
     *
     * @param e
     *            the e
     * @see java.awt.event.MouseListener#mouseEntered
     * (java.awt.event.MouseEvent)
     */
    public void mouseEntered(MouseEvent e) {
        System.out.println("Mouse Entered.");
    }

    /**
     * (non-Javadoc).
     *
     * @param e
     *            the e
     * @see java.awt.event.MouseListener#mouseExited
     * (java.awt.event.MouseEvent)
     */
    public void mouseExited(MouseEvent e) {
        System.out.println("Mouse exited.");
    }

    /**
     * (non-Javadoc).
     *
     * @param e
     *            the e
     * @see java.awt.event.MouseListener#mouseClicked
     * (java.awt.event.MouseEvent)
     */
    public void mouseClicked(MouseEvent e) {
    }

    /**
     * (non-Javadoc).
     *
     * @param e
     *            the e
     * @see java.awt.event.MouseMotionListener#mouseMoved
     * (java.awt.event.MouseEvent)
     */
    public void mouseMoved(MouseEvent e) {
    }

}

/**
 * The main method.
 *
 * @param args
 *            the arguments
 */
public static void main(String[] args) {
    new DrawTriangle();
}

};`

我的問(wèn)題是這段代碼基本上運(yùn)行正確，但我被告知旋轉(zhuǎn)的頂點(diǎn)必須在三角形的中間.我的是第一點(diǎn).

My issue is that this code basically runs correctly but I am told the vertex point of rotation has to be in the middle of the triangle. Mine is the first point.

推薦答案

先看看 2D 圖形，特別是變換形狀、文本、和圖片.

基本上，您的多邊形"將具有可定義的大小(最大 x/y 點(diǎn))，由此，您可以確定多邊形"的中心位置，例如...

Basically, your "polygon" will have a definable size (the maximum x/y point), from this, you can determine the center position of the "polygon", for example...

protected Dimension getTriangleSize() {
    int maxX = 0;
    int maxY = 0;
    for (int index = 0; index < xPoints.length; index++) {
        maxX = Math.max(maxX, xPoints[index]);
    }
    for (int index = 0; index < yPoints.length; index++) {
        maxY = Math.max(maxY, yPoints[index]);
    }
    return new Dimension(maxX, maxY);
}

這只是返回多邊形的最大 x 和 y 邊界.這允許您計(jì)算多邊形的中心位置.您馬上就會(huì)明白為什么您不需要實(shí)際指定原點(diǎn)...

This just returns the maximum x and y bounds of your polygon. This allows you to calculate the center position of the polygon. You'll see why in a second why you don't need to actually specify the origin point...

接下來(lái)，我們計(jì)算一個(gè)AffineTransform，就是直接應(yīng)用到Graphics上下文...

Next, we calculate a AffineTransform, which is the applied to the Graphics context directly...

Graphics2D g2d = (Graphics2D) g.create();
AffineTransform at = new AffineTransform();
Dimension size = getTriangleSize();
int x = clickPoint.x - (size.width / 2);
int y = clickPoint.y - (size.height / 2);
at.translate(x, y);
at.rotate(Math.toRadians(angle), clickPoint.x - x, clickPoint.y - y);
g2d.setTransform(at);
g2d.drawPolygon(xPoints, yPoints, 3);
// Guide
g2d.setColor(Color.RED);
g2d.drawLine(size.width / 2, 0, size.width / 2, size.height / 2);
g2d.dispose();

這不僅會(huì)平移三角形位置，還會(huì)旋轉(zhuǎn)它.這意味著您可以創(chuàng)建一個(gè)標(biāo)準(zhǔn)化多邊形(其原點(diǎn)為 0x0)并允許 Graphics 上下文將其放置在您想要的位置，這讓生活變得更加輕松......

This not only translates the triangle position, but will also rotate it. What this means you can create a normalised polygon (whose origin point is 0x0) and allow the Graphics context to place it where you want it, this makes life SO much easier...

現(xiàn)在，旋轉(zhuǎn)計(jì)算是基于計(jì)算兩點(diǎn)之間的角度，點(diǎn)擊"點(diǎn)和拖動(dòng)"點(diǎn)...

Now, the rotation calculation is based on calculating the angle between two points, the "click" point and the "drag" point...

angle = -Math.toDegrees(Math.atan2(e.getPoint().x - clickPoint.x, e.getPoint().y - clickPoint.y)) + 180;

這基于 this question

例如...

紅線是一個(gè)簡(jiǎn)單的指南，表明三角形的尖端指向鼠標(biāo)...

The red line is simple a guide to show that the tip of the triangle is point towards the mouse...

import java.awt.Color;
import java.awt.Dimension;
import java.awt.EventQueue;
import java.awt.Graphics;
import java.awt.Graphics2D;
import java.awt.Point;
import java.awt.event.MouseEvent;
import java.awt.event.MouseListener;
import java.awt.event.MouseMotionListener;
import java.awt.geom.AffineTransform;
import javax.swing.JFrame;
import javax.swing.JPanel;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;

public class DrawTriangle extends JFrame {

    /**
     * The x points.
     */
    private int[] xPoints = new int[]{0, 25, 50};

    /**
     * The y points.
     */
    private int[] yPoints = new int[]{50, 0, 50};

    double angle = 0f;

    /**
     * Instantiates a new draw triangle.
     */
    public DrawTriangle() {
        super("Dimitry Rakhlei");
        setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        setContentPane(new DrawTrianglePanel());
        pack();
        setLocationRelativeTo(null);
        setVisible(true);
    }

    /**
     * The Class DrawTrianglePanel.
     */
    private class DrawTrianglePanel extends JPanel implements MouseListener,
                    MouseMotionListener {

        private Point clickPoint;

        /**
         * Instantiates a new draw triangle panel.
         */
        public DrawTrianglePanel() {
            addMouseListener(this);
            addMouseMotionListener(this);
            clickPoint = new Point(100, 100);
        }

        @Override
        public Dimension getPreferredSize() {
            return new Dimension(200, 200);
        }

        protected Dimension getTriangleSize() {

            int maxX = 0;
            int maxY = 0;
            for (int index = 0; index < xPoints.length; index++) {
                maxX = Math.max(maxX, xPoints[index]);
            }
            for (int index = 0; index < yPoints.length; index++) {
                maxY = Math.max(maxY, yPoints[index]);
            }
            return new Dimension(maxX, maxY);
        }

        /**
         * Drawing the triangle.
         *
         * @param g the g
         * @see javax.swing.JComponent#paintComponent(java.awt.Graphics)
         */
        @Override
        protected void paintComponent(Graphics g) {
            super.paintComponent(g);

            Graphics2D g2d = (Graphics2D) g.create();
            AffineTransform at = new AffineTransform();
            Dimension size = getTriangleSize();
            int x = clickPoint.x - (size.width / 2);
            int y = clickPoint.y - (size.height / 2);
            at.translate(x, y);
            at.rotate(Math.toRadians(angle), clickPoint.x - x, clickPoint.y - y);
            g2d.setTransform(at);
            g2d.drawPolygon(xPoints, yPoints, 3);
            // Guide
            g2d.setColor(Color.RED);
            g2d.drawLine(size.width / 2, 0, size.width / 2, size.height / 2);
            g2d.dispose();

        }

        /**
         * (non-Javadoc).
         *
         * @param e the e
         * @see java.awt.event.MouseListener#mousePressed (java.awt.event.MouseEvent)
         */
        @Override
        public void mousePressed(MouseEvent e) {
            System.out.println("Mouse pressed called");
            //          clickPoint = e.getPoint();
            repaint();

        }

        /**
         * (non-Javadoc).
         *
         * @param e the e
         * @see java.awt.event.MouseListener#mouseReleased (java.awt.event.MouseEvent)
         */
        @Override
        public void mouseReleased(MouseEvent e) {
            System.out.println("Mouse released called");
        }

        /**
         * (non-Javadoc).
         *
         * @param e the e
         * @see java.awt.event.MouseMotionListener#mouseDragged (java.awt.event.MouseEvent)
         */
        public void mouseDragged(MouseEvent e) {
            System.out.println("Mouse dragged called");

            angle = -Math.toDegrees(Math.atan2(e.getPoint().x - clickPoint.x, e.getPoint().y - clickPoint.y)) + 180;

            repaint();
        }

        /**
         * (non-Javadoc).
         *
         * @param e the e
         * @see java.awt.event.MouseListener#mouseEntered (java.awt.event.MouseEvent)
         */
        public void mouseEntered(MouseEvent e) {
            System.out.println("Mouse Entered.");
        }

        /**
         * (non-Javadoc).
         *
         * @param e the e
         * @see java.awt.event.MouseListener#mouseExited (java.awt.event.MouseEvent)
         */
        public void mouseExited(MouseEvent e) {
            System.out.println("Mouse exited.");
        }

        /**
         * (non-Javadoc).
         *
         * @param e the e
         * @see java.awt.event.MouseListener#mouseClicked (java.awt.event.MouseEvent)
         */
        public void mouseClicked(MouseEvent e) {
        }

        /**
         * (non-Javadoc).
         *
         * @param e the e
         * @see java.awt.event.MouseMotionListener#mouseMoved (java.awt.event.MouseEvent)
         */
        public void mouseMoved(MouseEvent e) {
        }

    }

    /**
     * The main method.
     *
     * @param args the arguments
     */
    public static void main(String[] args) {
        EventQueue.invokeLater(new Runnable() {
            @Override
            public void run() {
                try {
                    UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
                } catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
                    ex.printStackTrace();
                }

                new DrawTriangle();
            }
        });
    }

}

現(xiàn)在，在你跳到我頭上抱怨解決方案太復(fù)雜"之前，請(qǐng)理解我是個(gè)白癡，說(shuō)真的，我 2 歲的孩子對(duì)基礎(chǔ)數(shù)學(xué)的掌握比我還好，這就是我能想出的最簡(jiǎn)單的解決方案不會(huì)融化我的大腦并使用雙陣列多邊形 API.就個(gè)人而言，我會(huì)使用 Shape API，但這不是你開(kāi)始使用的......

Now, before you jump all over me and complain that the solution is "too complex", understand that I'm an idiot, seriously, my 2 year old has a better grasp on basic mathematics then I do, this is the most simplistic solution I can come up with that doesn't melt my brain and uses the dual array polygon API. Personally, I'd use the Shape API, but that's not what you started with...

這篇關(guān)于圍繞點(diǎn)旋轉(zhuǎn)三角形java的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，也希望大家多多支持html5模板網(wǎng)！

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圍繞點(diǎn)旋轉(zhuǎn)三角形java

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