問題描述
我在這里掙扎和失敗了十多分鐘，我屈服了.我需要在 Swift 中將 Int 轉(zhuǎn)換為 Character，但無法解決.
I've struggled and failed for over ten minutes here and I give in. I need to convert an Int to a Character in Swift and cannot solve it.
問題
你如何將一個(gè) Int (integer) 轉(zhuǎn)換 (cast) 為一個(gè) Character (char) 在 Swift 中?
How do you convert (cast) an Int (integer) to a Character (char) in Swift?
說明性問題/任務(wù)挑戰(zhàn)
生成一個(gè) for 循環(huán)，打印字母 'A' 到 'Z'，例如像這樣:
Generate a for loop which prints the letters 'A' through 'Z', e.g. something like this:
推薦答案
不能將整數(shù)直接轉(zhuǎn)換為 Character 實(shí)例，但可以從整數(shù)轉(zhuǎn)換為 UnicodeScalar 到 Character 并再次返回:
You can't convert an integer directly to a Character instance, but you can go from integer to UnicodeScalar to Character and back again:
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