問題描述

我試圖在刪除某行之前檢查它是否存在.我的表中的行不存在，但它總是返回 1:

I am trying to check if a row exists before I delete it. The row in my table doesn't exist but it always returns 1:

$orders = $this->db->prepare("SELECT * FROM orders WHERE id=? AND user=?"); 
            $check = $orders->execute(array($message,$this->model->checkapi($data,$message)));
            echo $check;
            if($check){
            $deleteorder = $this->db->prepare("DELETE FROM orders WHERE id=? AND user=?"); 
            $deleteorder->execute(array($message,$this->model->checkapi($data,$message)));
                array_push($result, array('success' => true,
                                          'deleted' => $message));
                echo json_encode(array("result" => $result));
                die();
            }else{

$this->model->checkapi($data,$message)返回 fakeusername 和 id/$message 返回 136

$this->model->checkapi($data,$message) returns fakeusername and id/$message returns 136

我檢查了我的數(shù)據(jù)庫，ID 存在，但 ID 和用戶名不存在.

I've checked my database, the ID exists, but not the id and username together.

我正在發(fā)送 ID:136 和用戶名:fakeuser

I'm sending id: 136 and username: fakeuser

在數(shù)據(jù)庫中，該行以 id:136 和用戶名:demo 的形式存在.

in the databse the row exists as id:136 and username: demo.

我不知道為什么當由于不匹配而不應選擇該行時它會返回 1.

I'm not sure why it's returning 1 when the row shouldn't be selected due to it not matching.

推薦答案

你應該在 execute() 之后使用 fetch()，因為 execute() 只在成功時返回 TRUE 或在失敗時返回 FALSE :

You should use fetch() after execute(), because execute() just returns TRUE on success or FALSE on failure :

$orders->execute(...
$result = $orders->fetch(PDO::FETCH_ASSOC);
print_r($result);

這篇關于PDO 查詢總是返回 1 或 true的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網(wǎng)！