問題描述
我有兩個(gè)整數(shù)值 a 和 b，但我需要它們的浮點(diǎn)比率.我知道 a <b 并且我想計(jì)算 a/b，所以如果我使用整數(shù)除法，我將始終得到 0，余數(shù)為 a.
I have two integer values a and b, but I need their ratio in floating point. I know that a < b and I want to calculate a / b, so if I use integer division I'll always get 0 with a remainder of a.
如何在下面的 Python 中強(qiáng)制 c 為浮點(diǎn)數(shù)?
How can I force c to be a floating point number in Python in the following?
c = a / b
推薦答案
在 Python 2 中，兩個(gè)整數(shù)相除產(chǎn)生一個(gè)整數(shù).在 Python 3 中，它產(chǎn)生一個(gè)浮點(diǎn)數(shù).我們可以通過從 __future__ 導(dǎo)入來(lái)獲得新的行為.
In Python 2, division of two ints produces an int. In Python 3, it produces a float. We can get the new behaviour by importing from __future__.
>>> from __future__ import division
>>> a = 4
>>> b = 6
>>> c = a / b
>>> c
0.66666666666666663
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