問題描述

我在寫這個問題的答案時考慮了以下.

I thought about the following while writing an answer to this question.

假設我有一個像這樣深度嵌套的 xml 文件(但嵌套更多且更長):

Suppose I have a deeply nested xml file like this (but much more nested and much longer):

<section name="1">
    <subsection name"foo">
        <subsubsection name="bar">
            <deeper name="hey">
                <much_deeper name"yo">
                    <li>Some content</li>
                </much_deeper>
            </deeper>
        </subsubsection>
    </subsection>
</section>
<section name="2">
    ... and so forth
</section>

len(soup.find_all("section")) 的問題在于，在執行 find_all("section") 時，BS 一直在深入搜索一個標簽我知道不會包含任何其他 section 標記.

The problem with len(soup.find_all("section")) is that while doing find_all("section"), BS keeps searching deep into a tag that I know won't contain any other section tag.

那么，兩個問題:

1. 有沒有辦法讓 BS 不遞歸搜索到已經找到的標簽?
2. 如果對 1 的回答是肯定的，是效率更高還是內部流程相同?

1. Is there a way to make BS not search recursively into an already found tag?
2. If the answer to 1 is yes, will it be more efficient or is it the same internal process?

推薦答案

BeautifulSoup 不能只提供它找到的標簽的計數/數量.

BeautifulSoup cannot give you just a count/number of tags it found.

不過，您可以改進的是:不要讓 BeautifulSoup 通過傳遞 recursive=False 來搜索其他部分中的部分:

What you, though, can improve is: don't let BeautifulSoup go searching sections inside other sections by passing recursive=False:

len(soup.find_all("section", recursive=False))

除了改進之外，lxml 會更快地完成這項工作:

Aside from that improvement, lxml would do the job faster:

tree.xpath('count(//section)')

這篇關于BeautifulSoup 計數標簽而不深入解析它們的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！