<div id="selected"><ul class="可排序列表"></ul></div><div id="容器"><ul class="可排序列表"><li>1</li><li>2</li><li>....</li><li>9</li><li>10</li></ul></div>

第二:我想允許任何 5 個(gè) <li>s 從容器"到選定"div.如果有人試圖添加第 6 個(gè) <li>，那么它一定不允許用戶添加它.即第 6 個(gè) <li> 必須使用 jQuery 可拖動(dòng)選項(xiàng) revert.

即$("#container li").draggable({ revert: true });這是 javascript 代碼.

$(document).ready(function(){變量總計(jì) = 0;$("#selected").droppable({下降:函數(shù)(){總計(jì) = $("#selected li").length;//警報(bào)(總計(jì))；如果(總數(shù)> = 5){$("#container li").draggable({ revert: true });} 別的 {//下面的代碼不工作$("#container li").draggable({ revert: false });//這讓整個(gè)功能變得很奇怪.我可以拖動(dòng)所有的<li>任何地方}}});});

這工作正常.

第三:但是當(dāng)我將一個(gè) <li> 從selected"拖到container"時(shí)，selected"div 將只有 4 個(gè) <li>s.所以在這種情況下，稍后用戶應(yīng)該能夠?qū)⒘硪粋€(gè) <li> 從容器" div 添加到選定" div 中.但不幸的是，它不起作用.由于 if (total >= 5 ) 條件，我嘗試拖放到已選擇"中的所有 <li> 都將被還原.

誰能幫我解決這個(gè)問題，使用 draggable revert 選項(xiàng)?請(qǐng)...

你可以使用accept 選項(xiàng)，它需要一個(gè)函數(shù)來更容易地做到這一點(diǎn)，像這樣:

$("#selected ul").droppable({接受:函數(shù)(){return $("#selected li").length <5個(gè)；}});

你可以在這里測(cè)試一下.當(dāng)您將元素拖出時(shí)，.length 會(huì)下降，它會(huì)再次接受元素...沒有理由變得更復(fù)雜:)

I am having an issue related jQuery draggable and droppable. Here is description something what I want to do.

First: I have two divs. One is <div id="selected"> and another is <div id="container">. "container" has 10 <li> which are draggable and droppable into "selected". Here is code:

<div id="selected">
    <ul class="sortable-list">
    </ul>
</div>


<div id="container">
    <ul class="sortable-list">
             <li>1</li>
             <li>2</li>
             <li>....</li>
             <li>9</li>
             <li>10</li>
    </ul>
</div>

Second: I want to allow any 5 <li>s from "container" to "selected" div. If someone tries to add 6th <li>, then it must not allow user to it. That is the 6th <li> that is going to be inserted into "selected" must be reverted using jQuery draggable option revert.

i.e. $("#container li").draggable({ revert: true }); Here is javascript code for that.

$(document).ready(function(){

    var total = 0;
    $("#selected").droppable({
        drop: function() {
                total = $("#selected li").length;
                //alert(total);
                if (total >= 5) {
                    $("#container li").draggable({ revert: true });
                } else {
                            // below code is not working
                    $("#container li").draggable({ revert: false }); // this is making whole feature weird. I can drag all the <li> anywhere
                }
            }
    });
});

This is working fine.

Third: But when I drag an <li> from "selected" to "container", the "selected" div will have only 4 <li>s. So in this situation, later on user should be able to add another <li> into "selected" div from "container" div. But unfortunately it is not working. All the <li>s I try to drag and drop into "selected" are being reverted due to if (total >= 5 ) condition.

Can anyone help me to solve this out using draggable revert option? Please...

You can use the accept option which takes a function to do this much easier, like this:

$("#selected ul").droppable({
    accept: function() {
        return $("#selected li").length < 5;
    }
});

You can test it out here. When you drag elements out, the .length goes down and it'll accept elements again...no reason to get any more complicated :)

這篇關(guān)于基于條件的jQuery可拖動(dòng)還??原的文章就介紹到這了，希望我們推薦的答案對(duì)大家有所幫助，也希望大家多多支持html5模板網(wǎng)！