問(wèn)題描述
我有一個(gè) C++ Windows 程序.我有一個(gè)包含一些數(shù)據(jù)的文本文件.目前,文本文件是一個(gè)單獨(dú)的文件,它在運(yùn)行時(shí)加載并解析.如何將其作為資源嵌入到二進(jìn)制文件中?
I have a C++ Windows program. I have a text file that has some data. Currently, the text file is a separate file, and it is loaded at runtime and parsed. How is it possible to embed this into the binary as a resource?
推薦答案
由于您正在開(kāi)發(fā)本機(jī) Windows 應(yīng)用程序,因此您想要做的是創(chuàng)建一個(gè)用戶(hù)定義的資源,將文本文件的內(nèi)容嵌入到編譯后的資源.
Since you're working on a native Windows application, what you want to do is to create a user-defined resource to embed the contents of the text file into the compiled resource.
用戶(hù)定義資源的格式是記錄在MSDN,加載它的函數(shù).
The format of a user-defined resource is documented on MSDN, as are the functions for loading it.
您將文本文件嵌入到資源文件中,如下所示:
You embed your text file in a resource file like this:
nameID typeID filename
其中 nameID
是標(biāo)識(shí)資源的唯一 16 位無(wú)符號(hào)整數(shù),typeID
是標(biāo)識(shí)資源類(lèi)型的某個(gè)大于 255 的唯一 16 位無(wú)符號(hào)整數(shù)(您可以在 resource.h
文件中定義這些整數(shù)).filename
是您要將其二進(jìn)制內(nèi)容嵌入到已編譯資源中的文件的路徑.
where nameID
is some unique 16-bit unsigned integer that identifies the resource and typeID
is some unique 16-bit unsigned integer greater than 255 that identifies the resource type (you may define those integers in the resource.h
file). filename
is the path to the file that you want to embed its binary contents into the compiled resource.
所以你可能是這樣的:
在resource.h
中:
// Other defines...
#define TEXTFILE 256
#define IDR_MYTEXTFILE 101
在您的資源文件中:
#include "resource.h"
// Other resource statements...
IDR_MYTEXTFILE TEXTFILE "mytextfile.txt"
然后你像這樣加載它(為了清楚起見(jiàn)省略了錯(cuò)誤檢查代碼):
Then you load it like this (error-checking code omitted for clarity):
#include <windows.h>
#include <cstdio>
#include "resource.h"
void LoadFileInResource(int name, int type, DWORD& size, const char*& data)
{
HMODULE handle = ::GetModuleHandle(NULL);
HRSRC rc = ::FindResource(handle, MAKEINTRESOURCE(name),
MAKEINTRESOURCE(type));
HGLOBAL rcData = ::LoadResource(handle, rc);
size = ::SizeofResource(handle, rc);
data = static_cast<const char*>(::LockResource(rcData));
}
// Usage example
int main()
{
DWORD size = 0;
const char* data = NULL;
LoadFileInResource(IDR_MYTEXTFILE, TEXTFILE, size, data);
/* Access bytes in data - here's a simple example involving text output*/
// The text stored in the resource might not be NULL terminated.
char* buffer = new char[size+1];
::memcpy(buffer, data, size);
buffer[size] = 0; // NULL terminator
::printf("Contents of text file: %s
", buffer); // Print as ASCII text
delete[] buffer;
return 0;
}
請(qǐng)注意,您實(shí)際上不必釋放資源,因?yàn)橘Y源駐留在可執(zhí)行文件的二進(jìn)制文件中,系統(tǒng)會(huì)在程序退出時(shí)自動(dòng)刪除它們(函數(shù) FreeResource()
在 32 位和 64 位 Windows 系統(tǒng)上沒(méi)有任何內(nèi)容).
Note that you don't actually have to free the resource since the resource resides in the binary of the executable and the system will delete them automatically when the program exits (the function FreeResource()
does nothing on 32-bit and 64-bit Windows systems).
因?yàn)閿?shù)據(jù)駐留在可執(zhí)行二進(jìn)制文件中,您不能直接通過(guò)檢索到的指針修改它(這就是為什么 LoadFileInResource()
函數(shù)實(shí)現(xiàn)將指針存儲(chǔ)在 const char* 中的原因)
).您需要使用 BeginUpdateResource()
、UpdateResource()
和 EndUpdateResource()
函數(shù)來(lái)做到這一點(diǎn).
Because the data resides in the executable binary, you can't modify it via the retrieved pointer directly (that's why the LoadFileInResource()
function implementation stores the pointer in a const char*
). You need to use the BeginUpdateResource()
, UpdateResource()
, and EndUpdateResource()
functions to do that.
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