問題描述
使用 scanf，通常有一種直接獲取格式化輸入的方法:
With scanf there's, usually, a direct way to take formatted input:
1) 大于 0 且小于 1 的實(shí)數(shù)行.以x"結(jié)尾，例如:0.32432523x
1) line with a real number higher than 0, and less than 1. Ending on 'x', e.g: 0.32432523x
scanf("0.%[0-9]x", &number);
2) 行表示格式為:30+28=58
scanf(":%d+%d=%99s", &number1, &number2, &total);
cin的解決方法是什么，只用標(biāo)準(zhǔn)庫?
What is the cin solution, using only the standard library?
推薦答案
使用 >> 操作符讀取 cin.
Use the >> operator to read from cin.
int number1, number2;
std::string text;
char plus, equals;
std::cin >> number1 >> plus >> number2 >> equals >> text;
if (!std::cin.fail() && plus == '+' && equals == '=' && !text.empty())
std::cout << "matched";
它不如 scanf 好，因?yàn)槟仨氉约候?yàn)證 scanf 字符串中的任何文字.用流來做這件事幾乎肯定會(huì)比 scanf 要多得多的代碼行.
It's not as good as scanf because you'd have to verify any literals that were in the scanf string yourself. Doing it with streams will almost certainly be a lot more lines of code than scanf.
我會(huì)使用 scanf.
I would use scanf.
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