問題描述

我想使用 multiprocessing 模塊來完成這個.

I want to use multiprocessing module to complete this.

當我這樣做時，例如:

    $ python my_process.py

我啟動一個父進程，然后讓父進程產生一個子進程，

I start a parent process, and then let the parent process spawn a child process,

然后我希望父進程自行退出，但子進程繼續工作.

then i want that the parent process exits itself, but the child process continues to work.

請允許我寫一個錯誤代碼來解釋我自己:

Allow me write a WRONG code to explain myself:

from multiprocessing import Process

def f(x):
    with open('out.dat', 'w') as f:
        f.write(x)

if __name__ == '__main__':
    p = Process(target=f, args=('bbb',))
    p.daemon = True    # This is key, set the daemon, then parent exits itself
    p.start()

    #p.join()    # This is WRONG code, just want to exlain what I mean.
    # the child processes will be killed, when father exit

那么，我如何啟動一個在父進程完成時不會被殺死的進程?

So, how do i start a process that will not be killed when the parent process finishes?

20140714

大家好

我的朋友剛剛告訴我一個解決方案...

My friend just told me a solution...

我只是覺得……

不管怎樣，讓你看看:

import os
os.system('python your_app.py&')    # SEE!? the & !!

這確實有效！

推薦答案

一個技巧:調用os._exit 讓父進程退出，這樣守護子進程就不會被殺死.

A trick: call os._exit to make parent process exit, in this way daemonic child processes will not be killed.

但是還有一些其他的副作用，在 doc:

But there are some other side affects, described in the doc:

Exit the process with status n, without calling cleanup handlers, 
flushing stdio buffers, etc.

如果你不關心這個，你可以使用它.

If you do not care about this, you can use it.

這篇關于父進程退出時如何讓子進程存活?的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，也希望大家多多支持html5模板網！